The columns of grid are rendered first time, and then only data is fetched using ajax postback.
Most likely the new sql columns are not matching the rendered columns, and not loading data in it.
If you are changing sql that have different columns, you need to refresh page using location.reload();
There is not new columns, just change a parameter in my own filter criteria.
When user click on button "Show date", I wanna do a submit for same page, and show new data based on filter textbox. See steps below:
1 – original sql
2- Show grid with all data in firt time.
3 – User clik on button "Show date".
4 – in my php page ShowResults.php:
$bAction = $_POST['btnAction'];
$txtFilter = $_POST['txtDateFilter'];
// first accessing to page
$sql = "SELECT * FROM tb_test1";
$sql = "SELECT * FROM tb_test1 WHERE tb_test1.date=" . $txtFilter;
$g = new jqgrid();
$g->select_command = $sql;
$g->table = "tb_test1";
"SELECT * FROM tb_test1" is fine. But when user click on submit button, grid don't show data with new criteria ("SELECT * FROM tb_test1 WHERE tb_test1.date=" . $txtFilter).
I used echo $sql to check if $sql variable is ok.
So … How do I update my grid datasource?
Is there a "refresh" method to update grid datasource? Is ajax code necessary to show data based on new sql? If yes, how do it?
Thanks in advanced.
No special work required.
You need to preserve the $_POST data in session.
Refer this faq:
Q) How to load grid based on $_POST data from other page?
The grid is loaded with 2 server calls.
Now, if you want to pass data from external form, it is available for step1. But not there in 2nd ajax call, as it is not posted.
Solution is to put the POST variable in session and use it from session for step2.
$_SESSION["personid"] = $_POST["personid"];
$pid = $_SESSION["personid"];
and use `$pid` in your SQL.
It worked! Great 🙂
Now I have a new problem. I set $_SESSION["blablabla"] = "" in another page. But when I return to first page, the old Session value remains.
I love phpgrid and I really want to understand how it works.
I din't understand very well how phpgrid works with ajax call to update data. I read all examples, faq and documentation, but I didn't understand yet.
Please, can you show me phpgrid's life cycle?
Thanks in advanced.
If you are having a data persistence issue, you can have put check something like ..
if (non ajax call and no posted data)
I've not tested it but it should work.
$is_ajax = (!empty($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest');
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