Error with set_conditional_css, replace of null

QuestionsError with set_conditional_css, replace of null
Juan Pedro asked 3 years ago

Hi Abu,

I have one grid some complex, with some select2, css, etc. In first time onload all is correct, but  when I order, filter etc. it hangs on m.

I think it loads the data, it puts loading and the rows are left unformatted and I don’t see the information, but if I edit, the data is there (invisible).

The error that I get in the console is the following:

228 Uncaught TypeError: Cannot read property ‘replace’ of null

the error code is in follow underlined:



jQuery(‘#gbox_list1 .ui-jqgrid-bdiv’).not(‘.frozen-bdiv’).append(‘<div id=”div_no_record_list1″ align=”center” style=”padding:30px 0;”>’+jQuery.jgrid.defaults.emptyrecords+'</div>’);else





If delete code for set_conditional_cs then its ok..

part of code is

$f = array();
$f[“column”] = “PrimerArbitro_EstadoNominacion”; $f[“op”] = “eq”; $f[“value”] = “PR”; $f[“cellcss”] = “‘background-color’:’yellow'”;
$f_conditions[] = $f;

$f = array();
$f[“column”] = “PrimerArbitro_EstadoNominacion”; $f[“op”] = “eq”; $f[“value”] = “PC”; $f[“cellcss”] = “‘background-color’:’orange'”;
$f_conditions[] = $f;

$f = array();
$f[“column”] = “PrimerArbitro_EstadoNominacion”; $f[“op”] = “eq”; $f[“value”] = “R”; $f[“cellcss”] = “‘background-color’:’red'”;
$f_conditions[] = $f;


Is the problem with null value?

Is possible add code in $f= array to fix formatting when null.

Thank you.


1 Answers
Abu Ghufran Staff answered 3 years ago


I’ve emailed you an update, please recheck after updating.

Abu Ghufran - Dev Team
Grid 4 PHP Framework
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