Conditional Button

QuestionsConditional Button
Javier Lopez asked 9 years ago

Hello.

I have the next code:

$col = array();
$col["title"] = 'ENVIADO?';
$col["name"] = 'ds_enviado';
$col["width"] = '63';
$col["editable"] = false;
$col["frozen"] = true;
//$col["hidden"] = true;
$cols[] = $col;

(This Column only display 2 values: "S" or "N")

I need put a button in other Column only if the value of the column is "S"

In the Buttom Column i write:
$col["condition"] = $row["ds_id"] == "S";

But not work….

Can help me?
Thanks!

2 Answers
Abu Ghufran answered 9 years ago

For button column, you can set on_data_display event and in callback check value of row to show button.
e.g.

$col["on_data_display"] = array("display_button","");

function display_button($data)
{
$v = $data["ds_enviado"];
if ($v == "S")
return "<input type='button'>";
else
return "-";
}

Javier Lopez answered 9 years ago

Ok, Thanks!

But i use the next code….

$buttons_html_enviar = "<a target='_self' ….'>SOLICITAR</a>";
$buttons_html_ver = "<a target='_self' ….'>VER</a>";

$col["condition"] = array('$row["ds_enviado"] == "S"',$buttons_html_ver,$buttons_html_enviar);

$col["default"] = $buttons_html;

If the HTML of the $buttons_html_ver display a blank value works…

I think my method is not too profesional… but solved the problems

Thanks again a sorry for my english

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