Problem with php code before render

QuestionsProblem with php code before render
Akhlad asked 9 years ago

any php code before render is executed as many times as the render function is typed

for example I have some code

if ($_GET['do_some_stuff'] == 1){
// do some stuff;
}

………
………………….

g = new jqgrid();
$out = $g->render("list1");

What happens is the // do some stuff; part is executed 2 times

AND

if ($_GET['do_some_stuff'] == 1){
// do some stuff;
}

………
………………….

g1 = new jqgrid();
g2 = new jqgrid();
$ou1t = $g1->render("list1");
$out2 = $g2->render("list1");

What happens is the // do some stuff; part is executed 3 times

Huge issue

1 Answers
Abu Ghufran answered 9 years ago

The grid is loaded with 2 server calls.

1) load the columns of grid.
2) do an ajax call, to load data of grid.

When you have 2 grids, one call will load structure of both grids, and second+third ajax call for loading data of each grid.

For loading data, the ajax call have param 'grid_id' passed in $_GET, so if you want to run above code only once, you can put IF condition something like:

if (!isset($_GET["grid_id"]))
{
// once runnable code, when creating grid structure.
}

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