i have below code written inside grid
$g->select_command = "SELECT tbl_doner.Don_Id, tbl_doner.Don_Name,tbl_doner.Don_Contact,tbl_doner.Don_Email,tbl_grant.Gra_Type,tbl_grant.Gra_Amount FROM tbl_doner, tbl_grant WHERE
tbl_doner.Don_Id = tbl_grant.Don_Id AND Prj_Code = '$PrjCode'";
$out = $g_->render("list_APDonarInfo");
but echo $out not showing the grid with required records.
Appreciate your help
Q) How to load grid based on $_POST data from other page?
The grid is loaded with 2 server calls.
1) load the columns of grid.
2) do an ajax call, to load data of grid.
Now, if you want to pass data from external form, it is available for step1. But not there in 2nd ajax call, as it is not posted.
Solution is to put the POST variable in session and use it from session for step2.
$_SESSION["personid"] = $_POST["personid"];
$pid = $_SESSION["personid"];
and use `$pid` in your SQL.
Hi! And how make if the $_SESSION var change the value? Reload the grid dont work.
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