how to get the value in function

Questionshow to get the value in function
Chao Shun Jenq asked 10 years ago

Hi Abu,
****CODE1******

$col["name"] = "qty1";
$col["editable"] = true;

$col["name"] = "qty2";
$col["editable"] = true;

function test($data)
{
if ($data["params"]["qty1"]<$data["params"]["qty2"]) {phpgrid_error("error");}
}

****CODE2******

$col["name"] = "qty1";
$col["editable"] = true;

$col["name"] = "qty2";
$col["editable"] = false;

function test($data)
{
if ($data["params"]["qty1"]<$data["params"]["qty2"]) {phpgrid_error("error");}
}

********************
The CODE1 is work fine,but the CODE2 is not work.
Why I can not get the value of qty2 at CODE2 (using $data["params"]["qty2"] )??

Rgds,

4 Answers
Abu Ghufran answered 10 years ago

The reason for code2 is
$col["editable"] = false;

Non editable data is not posted by grid.
If you want it in function, you can make it editable->true, and keep it hidden.

You can also make another column with same column for display purpose.

$col["name"] = "qty2";
$col["editable"] = true;
$col["hidden"] = true;
..

$col["name"] = "qty2-temp";
$col["editable"] = false;

Chao Shun Jenq answered 10 years ago

Hi Abu
Thank for help!!
Rgds,

emman answered 9 years ago

Please how can I access the value of a col to use in a custom sql query
e.g.

$col["title"] = "School";
$col["name"] = "school";

….

$col["title"] = "Department";
$col["name"] = "department";
$schlquery = "select * from department WHERE schoolid='{school}'";

Is this possible?

I am using a paid version of the phpgrid

Abu Ghufran answered 9 years ago

I can't understand your query.
Please share code / screenshot. You can also email me at [email protected]

PS: Create a new ticket as it seems different case.

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